diketahui= AB=2-2√2
BC=1+√2
ditanya= panjang AC=.....?
BC=1+√2
ditanya= panjang AC=.....?
Jawaban:
[tex]15 + \sqrt{2} [/tex]
Penjelasan dengan langkah-langkah:
menggunakan rumus phytagoras
AC²=AB²+BC²
sehingga di dapatkan
AC² =
[tex](2 - 2 \sqrt{2} )^{2} + (1 + \sqrt{2} )^{2} \\ = (2 - 2 \sqrt{2})(2 - 2 \sqrt{2}) + \\ (1 - \sqrt{2})(1 - \sqrt{2} ) \\ = (4 - 4 \sqrt{2} - 4 \sqrt{2} + 8) + \\ ( 1 + \sqrt{2} + \sqrt{2} + 2)\\ = (12 - \sqrt{2} ) + (3 + 2 \sqrt{2} ) \\ = 15 + \sqrt{2} [/tex]
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